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OBJECTIVE SCIENCE QUIZ FOR ALL COMPETITION SERISE 44 BPSC 67th COMPLETE TEST 1

Directions (Q. Nos. 1-20) What approximate value should come in place of the question
mark(?) in the following questions? (Note that you are not expected to calculate the exact value).
1. (12.999)3= ? [IBPS Clerk 2011]
(a) 1800 (b) 1650 (c) 2000 (d) 2500 (e) 2200
2. 50550-5-50-5-5 = ? [IBPS Clerk 2011]
(a) 350 (b) 150 (c) 300 (d) 250 (e) 202
3. 49.0003 + 74.999 = ? [IBPS Clerk 2011]
(a) 0.05 (b) 0.2 (c) 1 (d) 0.7
(e) 2
4. 23.003 x 22.998 + 100.010 = ?
[IBPS Clerk 2011]
(a; 630 (b) 550 (c; 700 (d) 720 (e) 510
5. 125.009 + 69.999 + 104.989 = ?
[IBPS Clerk 2011]
(a) 420 (b) 300 (c; 285 (d 415 (e) 325
6. 16.003×27.998-209.010 = ?
[IBPS Clerk 2011]
(a) 150 (b; 200
(c) 75 (d) 240
(e; 110
7. 840.003-5-23.999 = ? [IBPS Clerk 2011]
(a; 47 (b) 8 (c; 35 (d) 18 (e; 23
8. 6885.009 – 419.999 – 94.989 = ?
[IBPS Clerk 2011]
(a) 6650 (b) 6830 (c) 6370 (c0 6200 (e; 6450
9. (9.95)2x(2.01)3 = 2x(?)2
[Dena Bank Clerk 2005]
(a) 12 (b) 15
(c; 25 (d) 20
(e)6
10.503×201 = ?
(a) 101100 (b) 1000000
(c; 110000 (c0 100003
14.36.98276421 x 21.00002 = ? [RBI 2003]
(a) 775 (b) 785 (c) 800 (d) 805 (e; 750
15.14.995 x 8.001 x 20.991 = ?
[Corporation Bank 2004]
fa; 1950 (b) 2520 (c) 2200 (d) 1520
(e; 2760
16.26.823 x 27.923 x 4.5001 = ? [RBI 2008]
(a) 3500 (b) 3450 (c) 3100 (of) 3150 (e; 3400
17.3739 + 164×27 = ?
[Canara Bank PO 2003]
(a) 105400 (b) 4000
(c) 8200 (d; 690
(e) 6300
18.21 + 3.7 x 2.9 = ? [Indian Bank PO 2003]
fa; 74 (b) 70 (c) 27 (d) 32
(e; 44
19. (21 + 99) x (30 – 19.02) = ?
[Indian Bank PO 2003]
(a) 3581 (b) 131
(c) 1290 (d) 1600
(e; None of the above
20.198.001 x 25 + 112.05 x 24.998 = ?
[Indian Bank PO 2003]
(a) 7570 (b) 7550 (c) 7500 (d) 7750 (e); 7250

Answer

1-e 2-e 3-d
3. (d) 49.0003 -s- 74.999 = 7
By rule 3 for division 49.0003 is decreased to 49 and 74.999 is increased to 75 So, 49-5-75 = ?
0.653 = ? => 7 = 0.7
(CO 23.003 x 22.998 + 100.010 = ? => 7=23×23+100
=> = 529 + 100 = 629
? = 630
5. (6) 125.009 + 69.999 + 104.989 = ? Using rule 1, each value is approximated to nearest whole number
=> ? =125 + 70 + 105 => ? = 300
6. (d) ? = 16.003 X 27.998 – 209.010
? = 16 X 28 – 210 = 448 – 210 ? = 238 = 240
7. (C) 7 = 840.003+23.999
Using rule 3, here one number is increased and other is decreased to their nearest whole number
= 840 +24 = 35
8. (C) ? = 6885.009 – 419.999 – 94.989
= 6885-420 -95=6370
9. (d
10. (a)
11-a 12-d 13-d
14. (a) 36.98276421 X 21.00002
Using rule 2, nearest value in whole number for 36.98276421 is 37 and 21.0002 is 21 = 37X21 = 777 = 775
15. (6) ? = 14.995 X 8.001 X 20.991
= 15X8X21 = 2520
16. (e) 26.823 X 27.923 X 4.5001
= 27 X 28 X 4.5000 = 756 X 4.5000 = 3402 = 3400
17. (c) 3739 + 164 X 27 = ?
? = 3739 + 4428 = 8167 = 8200
18. (d) 21 + 3.7 X 2.9 = ?
=> 7 = 21 + 4 X3=21 + 12 = 33 = 32
19. (e) (21 + 99) x (30 – 19.02)
(21 + 99) X (30 – 19)
= 120X11 = 1320
20. (d) ? = 198.001 X 25 + 112.05 X 24.998
= 198X25 + 112X25 = 25(198 + 112) = 25X310 = 7750

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