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OBJECTIVE SCIENCE QUIZ FOR ALL COMPETITION SERISE 44 BPSC 67th COMPLETE TEST 1

22. HCF and LCM of two numbers
are 7 and 140 respectively. If the
numbers are between 20 and
45, the sum of the numbers is :
(1) 70 (2) 77
(3) 63 (4) 56
(SSC CGL Prelim Exam. 11.05.2003
(First Sitting)
23. The number between 3000 and
4000 which is exactly divisible
by 30, 36 and 80 is
(1) 3625 (2) 3250
(3) 3500 (4) 3600
(SSC CHSL (10+2) DEO & LDC
Exam. 16.11.2014 , Ist Sitting
TF No. 333 LO 2)
24. Let x be the least number, which
when divided by 5, 6, 7 and 8
leaves a remainder 3 in each case
but when divided by 9 leaves no
remainder. The sum of digits of
x is
(1) 21 (2) 22
(3) 18 (4) 24
(SSC CGL Tier-II Exam,
25.10.2015, TF No. 1099685)
25. The greatest four digit number
which is exactly divisible by each
one of the numbers 12, 18, 21
and 28 is
(1) 9828 (2) 9288
(3) 9882 (4) 9928
(SSC CHSL (10+2) LDC, DEO & PA/SA
Exam, 01.11.2015, IInd Sitting)
26. A number x is divisible by 7.
When this number is divided by
8, 12 and 16. It leaves a remainder 3 in each case. The least
value of x is:
(1) 148 (2) 149
(3) 150 (4) 147
(SSC CHSL (10+2) LDC, DEO
& PA/SA Exam, 15.11.2015
(IInd Sitting) TF No. 7203752)
27. Let x be the smallest number,
which when added to 2000
makes the resulting number divisible by 12, 16, 18 and 21.
The sum of the digits of x is
(1) 7 (2) 5
(3) 6 (4) 4
(SSC CGL Tier-II Exam,
25.10.2015, TF No. 1099685)
28. The smallest five digit number
which is divisible by 12,18 and
21 is :
(1) 10224 (2) 30256
(3) 10080 (4) 50321
(SSC CHSL (10+2) LDC, DEO
& PA/SA Exam, 06.12.2015
(IInd Sitting) TF No. 3441135)
29. A number between 1000 and
2000 which when divided by 30,
36 and 80 gives a remainder 11
in each case is
(1) 1451 (2) 1641
(3) 1712 (4) 1523
(SSC CHSL (10+2) LDC, DEO
& PA/SA Exam, 20.12.2015
(Ist Sitting) TF No. 9692918)
30. The number between 4000 and
5000 that is divisible by each of
12, 18, 21 and 32 is
(1) 4023 (2) 4032
(3) 4302 (4) 4203
(SSC CHSL (10+2) LDC, DEO
& PA/SA Exam, 20.12.2015
(Ist Sitting) TF No. 9692918)
31. If the product of three consecutive numbers is 210 then sum of
the smaller number is :
(1) 3 (2) 4
(3) 5 (4) 11
(SSC CPO SI & ASI, Online
Exam. 06.06.2016) (IInd Sitting
answer:22. (3) 23. (4) 24. (3)
25. (1) 26. (4) 27. (1) 28. (3)
29. (1) 30. (2) 31. (4)

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