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are 7 and 140 respectively. If the

numbers are between 20 and

45, the sum of the numbers is :

(1) 70 (2) 77

(3) 63 (4) 56

(SSC CGL Prelim Exam. 11.05.2003

(First Sitting)

23. The number between 3000 and

4000 which is exactly divisible

by 30, 36 and 80 is

(1) 3625 (2) 3250

(3) 3500 (4) 3600

(SSC CHSL (10+2) DEO & LDC

Exam. 16.11.2014 , Ist Sitting

TF No. 333 LO 2)

24. Let x be the least number, which

when divided by 5, 6, 7 and 8

leaves a remainder 3 in each case

but when divided by 9 leaves no

remainder. The sum of digits of

x is

(1) 21 (2) 22

(3) 18 (4) 24

(SSC CGL Tier-II Exam,

25.10.2015, TF No. 1099685)

25. The greatest four digit number

which is exactly divisible by each

one of the numbers 12, 18, 21

and 28 is

(1) 9828 (2) 9288

(3) 9882 (4) 9928

(SSC CHSL (10+2) LDC, DEO & PA/SA

Exam, 01.11.2015, IInd Sitting)

26. A number x is divisible by 7.

When this number is divided by

8, 12 and 16. It leaves a remainder 3 in each case. The least

value of x is:

(1) 148 (2) 149

(3) 150 (4) 147

(SSC CHSL (10+2) LDC, DEO

& PA/SA Exam, 15.11.2015

(IInd Sitting) TF No. 7203752)

27. Let x be the smallest number,

which when added to 2000

makes the resulting number divisible by 12, 16, 18 and 21.

The sum of the digits of x is

(1) 7 (2) 5

(3) 6 (4) 4

(SSC CGL Tier-II Exam,

25.10.2015, TF No. 1099685)

28. The smallest five digit number

which is divisible by 12,18 and

21 is :

(1) 10224 (2) 30256

(3) 10080 (4) 50321

(SSC CHSL (10+2) LDC, DEO

& PA/SA Exam, 06.12.2015

(IInd Sitting) TF No. 3441135)

29. A number between 1000 and

2000 which when divided by 30,

36 and 80 gives a remainder 11

in each case is

(1) 1451 (2) 1641

(3) 1712 (4) 1523

(SSC CHSL (10+2) LDC, DEO

& PA/SA Exam, 20.12.2015

(Ist Sitting) TF No. 9692918)

30. The number between 4000 and

5000 that is divisible by each of

12, 18, 21 and 32 is

(1) 4023 (2) 4032

(3) 4302 (4) 4203

(SSC CHSL (10+2) LDC, DEO

& PA/SA Exam, 20.12.2015

(Ist Sitting) TF No. 9692918)

31. If the product of three consecutive numbers is 210 then sum of

the smaller number is :

(1) 3 (2) 4

(3) 5 (4) 11

(SSC CPO SI & ASI, Online

Exam. 06.06.2016) (IInd Sitting

answer:22. (3) 23. (4) 24. (3)

25. (1) 26. (4) 27. (1) 28. (3)

29. (1) 30. (2) 31. (4)